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398
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1 def load(resource):
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2 """
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3 open a file or URL for reading. If the passed resource string is not a URL,
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4 or begins with 'file://', return a ``file``. Otherwise, return the
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5 result of urllib2.urlopen()
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6 """
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7
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8 # handle file URLs separately due to python stdlib limitations
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9 if resource.startswith('file://'):
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10 resource = resource[len('file://'):]
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11
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12 if not is_url(resource):
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13 # if no scheme is given, it is a file path
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14 return file(resource)
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15
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16 return urllib2.urlopen(resource) |
